JEE Main & Advanced Physics Ray Optics Question Bank Microscope and Telescope

  • question_answer
    In a compound microscope, the focal lengths of two lenses are 1.5 cm and 6.25 cm an object is placed at 2 cm form objective and the final image is formed at 25 cm from eye lens. The distance between the two lenses is [EAMCET (Med.) 2000]

    A)            6.00 cm                                   

    B)            7.75 cm

    C)            9.25 cm                                   

    D)            11.00 cm

    Correct Answer: D

    Solution :

     \[L={{v}_{o}}+{{u}_{e}}=\frac{{{u}_{o}}{{f}_{o}}}{({{u}_{o}}-{{f}_{o}})}+\frac{{{f}_{e}}D}{{{f}_{e}}+D}\]            \[\Rightarrow L=\frac{2\times 1.5}{(2-1.5)}+\frac{6.25\times 25}{(6.25+25)}=11\ cm\]


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