A) 0.08 mm
B) 0.10 mm
C) 0.12 mm
D) 0.06 mm
Correct Answer: A
Solution :
Resolving limit \[x\propto \lambda \Rightarrow \frac{{{x}_{1}}}{{{x}_{2}}}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\Rightarrow \frac{0.1}{{{x}_{2}}}=\frac{6000}{4800}\]\[\Rightarrow {{x}_{2}}=0.08\ mm\]
You need to login to perform this action.
You will be redirected in
3 sec
