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JEE Main & Advanced Physics Ray Optics Question Bank Microscope and Telescope

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    Wavelength of light used in an optical instrument are \[{{\lambda }_{1}}=4000\]Å and \[{{\lambda }_{2}}=5000\]Å, then ratio of their respective resolving power (corresponding to \[{{\lambda }_{1}}\]and \[{{\lambda }_{2}})\]is  [AIEEE 2002]

    A)            16 : 25                                     

    B)            9 : 1

    C)            4 : 5                                          

    D)            5 : 4

    Correct Answer: D

    Solution :

               R.P. \[\propto \frac{1}{\lambda }\Rightarrow \frac{{{(R.P.)}_{1}}}{{{(R.P.)}_{2}}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{5}{4}\]


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