JEE Main & Advanced Physics Ray Optics Question Bank Microscope and Telescope

  • question_answer
    The length of an astronomical telescope for normal vision (relaxed eye) (fo = focal length of objective lens and fe  = focal length of eye lens) is [EAMCET (Med.) 1995; CPMT 1999; BVP 2003]

    A)            \[{{f}_{o}}\times {{f}_{e}}\]  

    B)            \[\frac{{{f}_{o}}}{{{f}_{e}}}\]

    C)            \[{{f}_{o}}+{{f}_{e}}\]      

    D)            \[{{f}_{o}}-{{f}_{e}}\]

    Correct Answer: C

    Solution :


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