A) 19
B) 23
C) 25
D) 31
Correct Answer: D
Solution :
In fig (A), \[{{6}^{2}}=36,\]\[{{8}^{2}}=64,\]\[{{5}^{2}}=25,\]\[{{7}^{2}}=49\]and \[6+8+5+7=26\] In fig (B), \[{{3}^{2}}=9,\]\[{{5}^{2}}=25,\]\[{{4}^{2}}=16,\]\[{{9}^{2}}=81\]and \[3+5+4+9=21\] In fig (C), \[{{5}^{2}}=25,\]\[{{12}^{2}}=144,\]\[{{6}^{2}}=36,\]\[{{8}^{2}}=64.\] So, missing number\[=5+12+6+8=31.\]
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