A) 4, 2 and 12
B) 5, 11 and 17
C) 10, 9 and 4
D) 5, 3 and 2
Correct Answer: A
Solution :
\[F-B=C\] \[B+C+F=E\] \[E\text{/}F=A\] \[A\times C+F=D\]
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