A) First
B) Second
C) Third
D) Fourth
Correct Answer: C
Solution :
[c] Milk in first container \[=\frac{5}{8}=0.625\] Milk in second container \[=\frac{2}{3}=0.66\] Milk in third container \[=\frac{3}{5}=0.6\] Milk in fourth container \[=\frac{7}{11}=0.636\] So, it is clear that quantity of milk relative to water is minimum in third container. |
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