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SSC Quantitative Aptitude Mixture And Alligation Question Bank Mixture and Allegation (I)

  • question_answer
    A and B are two alloys of gold and copper prepared by mixing metals in the ratio 7 : 2 and 7 : 11, respectively. If equal quantities of the alloys are melted to form a third alloy C, the ratio of gold and copper in C will be

    A) 5 : 7

    B) 5 : 9

    C) 7 : 5

    D) 9 : 5

    Correct Answer: C

    Solution :

    [c]
    Gold Copper
    Alloy A \[\frac{7}{9}\] \[\frac{2}{9}\]
    Alloy B \[\frac{7}{18}\] \[\frac{11}{18}\]
    Since, alloys A and B are melted in the ratio 1 : 1 to make the alloy, therefore in the alloy C, the ratio of gold and copper. \[\left( \frac{7}{9}\times \frac{1}{2}+\frac{7}{18}\times \frac{1}{2} \right):\left( \frac{2}{9}\times \frac{1}{2}+\frac{11}{18}\times \frac{1}{2} \right)\] \[=\left( \frac{7}{9}+\frac{7}{18} \right):\left( \frac{2}{9}+\frac{11}{18} \right)\] \[=\frac{21}{18}:\frac{15}{18}=21:15=7:5\]


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