SSC Quantitative Aptitude Mixture And Alligation Question Bank Mixture and Allegation (II)

  • question_answer
    There are three bottles of mixture of syrup and water of ratios \[2:3,\]\[3:4\] and \[7:5.\]\[10\,L\]of first and 21 L of second bottles are taken. How much quantity from third bottle is to be taken so that final mixture from three bottles will be of ratios \[1:1.\] [SSC CGL Tier II, 2017]

    A) \[25\,L\]

    B) \[20\,L\]

    C) \[35\,L\]

    D) \[30\,L\]

    Correct Answer: D

    Solution :

    [d]   In first bottle, syrup \[=\frac{2}{5}\times 10=4\,L\] Water \[=\frac{3}{5}\times 10=6\,L\] In second bottle, syrup \[=\frac{3}{7}\times 21=9\,L\] Water \[=\frac{4}{7}\times 21=12\,L\] Let, mixture taken out from third bottle \[=x\,L\] \[\therefore \] In third bottle, syrup \[=\frac{7}{12}\times x=\frac{7x}{12}L\] Water \[=\frac{5}{12}\times x=\frac{15x}{12}L\] Now, according to the question,                         \[\frac{4+9+\frac{7x}{12}}{6+12+\frac{5x}{12}}=\frac{1}{1}\] \[\Rightarrow \]               \[13+\frac{7x}{12}=18+\frac{5x}{12}\] \[\Rightarrow \]               \[\frac{7x}{12}-\frac{5x}{12}=18-13\] \[\Rightarrow \]                           \[\frac{2x}{12}=5\] \[\Rightarrow \]               \[x=\frac{5\times 12}{2}\] \[\Rightarrow x=30\,L\]


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