A) 1 : 6
B) 2 : 3
C) 4 : 3
D) 6 : 1
Correct Answer: D
Solution :
[d] Let the CP of the milk be Rs. 100 per liter. Then, SP of 100 L of mixture = Rs. 100, Gain per cent \[=\frac{50}{3}%\] The required ratio \[=\frac{\text{Milk}}{\text{Water}}\] \[=\frac{100}{16\frac{2}{3}}=\frac{100\times 3}{50}=\frac{6}{1}=6:1\] |
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