A) \[25\,L\]
B) \[20\,L\]
C) \[35\,L\]
D) \[30\,L\]
Correct Answer: D
Solution :
[d] In first bottle, syrup \[=\frac{2}{5}\times 10=4\,L\] Water \[=\frac{3}{5}\times 10=6\,L\] In second bottle, syrup \[=\frac{3}{7}\times 21=9\,L\] Water \[=\frac{4}{7}\times 21=12\,L\] Let, mixture taken out from third bottle \[=x\,L\] \[\therefore \] In third bottle, syrup \[=\frac{7}{12}\times x=\frac{7x}{12}L\] Water \[=\frac{5}{12}\times x=\frac{15x}{12}L\] Now, according to the question, \[\frac{4+9+\frac{7x}{12}}{6+12+\frac{5x}{12}}=\frac{1}{1}\] \[\Rightarrow \] \[13+\frac{7x}{12}=18+\frac{5x}{12}\] \[\Rightarrow \] \[\frac{7x}{12}-\frac{5x}{12}=18-13\] \[\Rightarrow \] \[\frac{2x}{12}=5\] \[\Rightarrow \] \[x=\frac{5\times 12}{2}\] \[\Rightarrow x=30\,L\] |
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