question_answer

\[{{C}_{2}}{{H}_{2}}\xrightarrow[Dil.{{H}_{2}}S{{O}_{4}}]{HgS{{O}_{4}}}P\xrightarrow{(0)}\] \[Q\xrightarrow[Pyridine]{SOC{{l}_{2}}}R\xrightarrow{{{({{C}_{2}}{{H}_{5}})}_{2}}Cd}S\] The end product in the above sequence of reactions is

A) Ethylethanal      

B) 2-Butanone

C) Propanal           

D) Propanone

Correct Answer: B

Solution :

[b] \[HC\equiv CH\xrightarrow{HgS{{O}_{4}}/{{H}^{+}}}\underset{(P)}{\mathop{C{{H}_{3}}CHO}}\,\xrightarrow{[o]}\]