A) \[\pi {{a}^{2}}\]sq. units
B) \[\frac{3\pi \,{{a}^{2}}}{2}\] sq. units
C) \[2\pi \,{{a}^{2}}\]sq. units
D) \[3\pi \,{{a}^{2}}\] sq. units
Correct Answer: B
Solution :
[b] The required area \[A=\int_{0}^{2a}{\sqrt{\frac{{{x}^{3}}}{2a-x}}dx}\]You need to login to perform this action.
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