A) 1.73
B) 2.84
C) 4.90
D) 0
Correct Answer: B
Solution :
[b] \[Ni=28={{[Ar]}^{18}}3{{d}^{8}}4{{s}^{2}};N{{i}^{2+}}={{[Ar]}^{18}}3{{d}^{8}}\] \[N{{i}^{2+}}\] has two unpaired electrons. \[\therefore \mu =\sqrt{n(n+2)}\] \[=\sqrt{8}=2.84BM\]You need to login to perform this action.
You will be redirected in
3 sec