A) \[\frac{{{\varepsilon }_{0}}A}{d}\]
B) \[\frac{3{{\varepsilon }_{0}}A}{d}\]
C) \[\frac{3}{2}\frac{{{\varepsilon }_{0}}A}{d}\]
D) \[\frac{2{{\varepsilon }_{0}}A}{d}\]
Correct Answer: D
Solution :
[d] The given circuit is equivalent to parallel combination of two identical capacitors, each having compacitane. \[C=\frac{{{\varepsilon }_{0}}A}{d}.\]Hence \[{{C}_{eq}}=2C=\frac{2{{\varepsilon }_{0}}A}{d}\]
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