question_answer

The capacities and connection of. five capacitors are shown in the adjoining figure. The potential difference between the points A and B is 60 volts. Then the equivalent capacity between A and B and the charge on \[5\mu F\] capacitance will be respectively

A) \[44\mu F;\,\,300\mu C\]

B) \[16\mu F;\,\,150\mu C\]

C) \[15\mu F;\,\,200\mu C\]

D) \[4\mu F;\,\,50\mu C\]

Correct Answer: D

Solution :

[d] The given circuit can be redrawn as follows Equivalent capacitance of the circuit \[{{C}_{AB}}=4\mu F\] Charge given by the battery \[Q={{C}_{eq}}V=4\times 60=240\mu C\] Charge in \[5\mu F\]capacitor \[Q'=\frac{5}{(10+5+9)}\times 240=50\mu c\]