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JEE Main & Advanced Physics Electrostatics & Capacitance Question Bank Mock Test - Capacitance

  • question_answer
    For section AB of a circuit shown in figure,\[{{C}_{1}}=1\mu F\], \[{{C}_{2}}=2\mu F\], \[E=10V\], and the potential difference \[{{V}_{A}}-{{V}_{B}}=10V\]. Charge on capacitor \[{{C}_{1}}\] is

    A) \[0\mu C\]         

    B) \[20/3\mu C\]

    C) \[40/3\mu C\]    

    D) None of these

    Correct Answer: C

    Solution :

    [c] \[{{V}_{A}}-\frac{q}{{{C}_{1}}}-E-\frac{q}{{{C}_{2}}}={{V}_{B}}\] or \[{{V}_{A}}-{{V}_{B}}-E=q\left( \frac{1}{{{C}_{1}}}+\frac{1}{{{C}_{2}}} \right)\] or \[q=-\frac{40}{3}\mu C\]


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