JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Mock Test - Chemical Equilibrium

  • question_answer
    What is the equilibrium constant for the reaction? \[{{P}_{4(s)}}+5{{O}_{2(g)}}\rightleftarrows {{P}_{4}}{{O}_{10(s)}}\]

    A) \[{{K}_{C}}=\frac{1}{{{\left[ {{O}_{2}} \right]}^{5}}}\]         

    B) \[{{K}_{C}}=\frac{\left[ {{P}_{4}}{{O}_{10}} \right]}{5\left[ {{P}_{4}} \right]\left[ {{O}_{2}} \right]}\]

    C) \[{{K}_{C}}={{\left[ {{O}_{2}} \right]}^{5}}\]            

    D) \[{{K}_{C}}=\frac{\left[ {{P}_{4}}{{O}_{10}} \right]}{5\left[ {{P}_{4}} \right]{{\left[ {{O}_{2}} \right]}^{5}}}\]

    Correct Answer: A

    Solution :

    [a]  Concentration of solid species is supposed to be unity. \[\therefore {{K}_{C}}=\frac{1}{{{[{{O}_{2}}]}^{5}}}\]         


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