| (1) \[C{{O}_{(g)}}+{{H}_{2}}{{O}_{(g)}}\rightleftarrows C{{O}_{2(g)}}+{{H}_{2(g)}};{{K}_{1}}\] |
| (2) \[C{{H}_{4(g)}}\]\[+{{H}_{2}}{{O}_{(g)}}\rightleftarrows \]\[C{{O}_{(g)}}\]\[3{{H}_{2(g)}};{{K}_{2}}\] |
| (3) \[C{{H}_{4(g)}}+2{{H}_{2}}{{O}_{(g)}}\rightleftarrows C{{O}_{2(g)}}+4{{H}_{2(g)}};{{K}_{3}}\] |
A) \[{{K}_{1}}\sqrt{{{K}_{2}}}={{K}_{3}}\]
B) \[{{K}_{2}}{{K}_{3}}={{K}_{1}}\]
C) \[{{K}_{3}}={{K}_{1}}{{K}_{2}}\]
D) \[{{K}_{3}}.\,{{K}^{3}}_{2}={{K}^{2}}_{1}\]
Correct Answer: C
Solution :
[c] \[CO(g)+{{H}_{2}}O(g)\rightleftharpoons C{{O}_{2}}(g)+{{H}_{2}}(g);{{K}_{1}}\] (1) \[C{{H}_{4}}(g)+{{H}_{2}}O(g)\rightleftharpoons CO(g)+3{{H}_{2}}(g);{{K}_{2}}\] (2) \[C{{H}_{4}}+2{{H}_{2}}O(g)\rightleftharpoons C{{O}_{2}}(g)+4{{H}_{2}}(g);{{K}_{3}}\] (3) Eq. (3) = eq. (1)+eq.(2) Thus, \[{{K}_{3}}={{K}_{1}}.{{K}_{2}}\]
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