JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Mock Test - Chemical Equilibrium

  • question_answer
    The standard Gibbs energy change at 300 K for the reaction \[2A\to B+C\]is 2494.2J. At a given time, the composition of the reaction mixture is [A]=\[\frac{1}{2},[B]=2\,and\,(C)=\frac{1}{2}\]. [R=8.314J/Kmol, e=2.718]

    A) forward direction because \[Q>{{K}_{C}}\]

    B) reverse direction because \[Q>{{K}_{C}}\]

    C) forward direction because \[Q<{{K}_{C}}\]

    D) reverse direction because \[Q<{{K}_{C}}\]

    Correct Answer: B

    Solution :

    [b] \[\Delta G=\Delta {{G}^{o}}+RT\]In Q \[=249.2+8.314\times 300\] In 4 =Positive \[\Delta G=RT\]In \[\frac{Q}{K}\] Since, \[\Delta G\]is positive so Q>K, so reaction shifts in reverse direction.


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