A) \[K=K'\]
B) \[K'=\sqrt{K}\]
C) \[K=\sqrt{K'}\]
D) \[K\times K'=1\]
Correct Answer: B
Solution :
[b] \[{K}'=\text{ }{{K}^{n}};\,\,Hence\,\,n=\frac{1}{2}\] \[\therefore {K}'={{K}^{1/2}}=\sqrt{K}\]You need to login to perform this action.
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