A) \[{{(2{{K}_{P}}/P)}^{1/3}}\]
B) \[{{(2{{K}_{P}}/P)}^{1/2}}\]
C) \[({{K}_{P}}/P)\]
D) \[(2{{K}_{P}}/P)\]
Correct Answer: A
Solution :
[a] \[\underset{\underset{1-x}{\mathop{1}}\,}{\mathop{2A{{B}_{2}}}}\,(g)\rightleftharpoons \underset{\underset{x}{\mathop{0}}\,}{\mathop{2AB}}\,(g)+\underset{\underset{x/2}{\mathop{0}}\,}{\mathop{{{B}_{2}}}}\,(g)\] \[\therefore Kp=\frac{{{x}^{2}}.x}{2{{(1-x)}^{2}}}.\left[ \frac{P}{1+\frac{x}{2}} \right]=\frac{{{x}^{2}}.P}{2}\] \[(1-x\approx 1\,and\,1+\frac{x}{2}\approx 1,Since\,x<<1)\] Or \[P=\sqrt[3]{\frac{2Kp}{P}}\]
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