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JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Mock Test - Chemical Kinetics

  • question_answer
    In the formation of sulphur trioxide by the contact process, \[2S{{O}_{2}}+{{O}_{2}}\rightleftharpoons 2S{{O}_{3}}\], the rate of reaction was measured as  \[\frac{d[{{O}_{2}}]}{dt}=3.0\times {{10}^{-4}}mol\,{{L}^{-1}}{{s}^{-1}}\]. The rate of reaction expressed in terms of \[S{{O}_{3}}\] will be

    A) \[3.0\times {{10}^{-4}}mol\,{{L}^{-1}}{{s}^{-1}}\]

    B) \[6.0\times {{10}^{-4}}mol\,{{L}^{-1}}{{s}^{-1}}\]

    C) \[1.5\times {{10}^{-4}}mol\,{{L}^{-1}}{{s}^{-1}}\]

    D) \[4.5\times {{10}^{-4}}mol\,{{L}^{-1}}{{s}^{-1}}\]  

    Correct Answer: B

    Solution :

    [b] \[-\frac{d[{{O}_{2}}]}{dt}=+\frac{1}{2}\frac{d[S{{O}_{3}}]}{dt}\] \[3\times {{10}^{-4}}=\frac{1}{2}\frac{d[S{{O}_{3}}]}{dt}\] \[\frac{d[S{{O}_{3}}]}{dt}=6\times {{10}^{-4}}M/sec.\]


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