A) 6.932 mm
B) 100 min
C) \[0.6932\text{ }\times {{10}^{-3}}\min \]
D) \[0.6932\text{ }\times {{10}^{-2}}\min \]
Correct Answer: B
Solution :
[b] \[r=k{{[reactant]}^{-1}}\] \[\therefore k=\frac{0.693\times {{10}^{-2}}}{1}\] Also \[{{t}_{1/2}}=\frac{0.693}{k}=\frac{0.693}{0.693\times {{10}^{-2}}}=100\min \]You need to login to perform this action.
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