A) 17.49 mL
B) 27.49 mL
C) 37.49 mL
D) 47.49 mL
Correct Answer: A
Solution :
[a] Given k = 0.008 \[{{\min }^{-1}}\] From \[\therefore k=\frac{2.303}{t}\log \frac{{{V}_{\infty }}}{{{V}_{\infty }}-{{V}_{t}}}\] \[\Rightarrow 0.008=\frac{2.303}{20}\log \frac{{{V}_{\infty }}}{{{V}_{\infty }}-16}\] \[\Rightarrow 0.0695=\log \frac{{{V}_{\infty }}}{{{V}_{\infty }}-16}\] \[\Rightarrow {{V}_{\infty }}=17.49mL\]
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