A) \[\frac{B}{T}+C\,\log \,T\]
B) \[[2.303\,B+CT]R\]
C) C log T
D) B + CTR
Correct Answer: B
Solution :
[b] \[\log k=A-\frac{B}{T}+C\log T\] Or In \[k=2.303A-\frac{B\times 2.303}{T}+C\]In T \[\frac{d\, Ink}{dT}=\left[ \frac{2.303B}{{{T}^{2}}}+\frac{C}{T} \right],\frac{d( Ink)}{dt}=\frac{{{E}_{a}}}{R{{T}^{2}}}\] \[{{E}_{a}}=[2.303B+CT]R.\]
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