A) Saponification of \[C{{H}_{3}}COOC{{H}_{5}}\]- Second order reaction
B) Hydrolysis of \[C{{H}_{3}}COOC{{H}_{3}}\]- Pseudo unimolecular reaction
C) Decomposition of \[{{H}_{2}}{{O}_{2}}\]- First order reaction
D) Combination of \[{{H}_{2}}\] and \[{{B}_{2}}\] to give HBr -Zero order reaction
Correct Answer: D
Solution :
[d] \[{{H}_{2}}+B{{r}_{2}}\rightleftharpoons 2HBr\] is a 1.5 order reaction i.e., \[K=[{{H}_{2}}]{{[B{{r}_{2}}]}^{1/2}}\]
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