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JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Mock Test - Chemical Kinetics

  • question_answer
    The rate for a first order reaction is \[0.6932\text{ }\times {{10}^{-2}}mol\,{{L}^{-1}}\] and the initial concentration of the reactants is 1 M, \[{{T}_{1/2}}\] is equal to

    A) 6.932 mm         

    B) 100 min

    C) \[0.6932\text{ }\times {{10}^{-3}}\min \]

    D) \[0.6932\text{ }\times {{10}^{-2}}\min \]

    Correct Answer: B

    Solution :

    [b] \[r=k{{[reactant]}^{-1}}\] \[\therefore k=\frac{0.693\times {{10}^{-2}}}{1}\] Also \[{{t}_{1/2}}=\frac{0.693}{k}=\frac{0.693}{0.693\times {{10}^{-2}}}=100\min \]


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