A) -204 kcal
B) -108 kcal
C) -9 kcal
D) +9 kcal
Correct Answer: B
Solution :
[b] \[\Delta H=\Delta U+\Delta {{n}_{g}}RT\] \[-109=\Delta U+\left( \frac{-1\times 2\times 500}{1000} \right)kcal\] \[-109=\Delta U-1\,kcal\] \[\Delta U=-109+1=-108\,kcal\]You need to login to perform this action.
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