A) -1083 kJ \[mo{{l}^{-1}}\]
B) -108.3 kJ \[mo{{l}^{-1}}\]
C) -10.83 kJ \[mo{{l}^{-1}}\]
D) -1.083 kJ \[mo{{l}^{-1}}\]
Correct Answer: A
Solution :
[a] \[3U{{O}_{2}}+{{O}_{2}}\to {{U}_{3}}{{O}_{8}}\] \[\Delta H{}^\circ =\Delta H_{f}^{\circ }({{U}_{3}}{{O}_{8}})-\Delta H_{f}^{\circ }({{O}_{2}})-3\Delta H_{f}^{\circ }(U{{O}_{2}})\] \[\Rightarrow 3\Delta H_{f}^{\circ }(U{{O}_{2}})=-\Delta H_{f}^{\circ }+\Delta H_{f}^{\circ }({{U}_{3}}{{O}_{8}})-\Delta H_{f}^{\circ }({{O}_{2}})\] or \[\Delta H_{f}^{\circ }(U{{O}_{2}})=\frac{-(-76.0)+(-853.5)-0}{3}\]
You need to login to perform this action.
You will be redirected in
3 sec
