JEE Main & Advanced Chemistry Thermodynamics / रासायनिक उष्मागतिकी Question Bank Mock Test - Chemical Thermodynamics

  • question_answer
    The enthalpies of combustion of carbon and carbon monoxide are -390 kJ and -278 kJ respectively. The enthalpy of formation of CO in kJ is

    A) 668                  

    B) 112

    C)  -112                

    D) -668

    Correct Answer: C

    Solution :

    [c] \[C+{{O}_{2}}\to C{{O}_{2}};\Delta H=-290kJ\]                        (1) \[CO+\frac{1}{2}{{O}_{2}}\to C{{O}_{2}};\Delta H=-278\,kJ\] (2) By eq. (1) and eq. (2), we get \[C+\frac{1}{2}{{O}_{2}}\to CO;\Delta H=-112\,kJ\]


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