A) \[pV\]
B) \[2pV\]
C) \[\frac{1}{2}pV\]
D) zero
Correct Answer: A
Solution :
[a] The work done during the cyclic path is equal to the area enclosed by the path, which is pV. Work done \[=(2p-p)(2V-V)=pV\]You need to login to perform this action.
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