A) +170 kcal
B) +526 kcal
C) -170 kcal
D) -526 kcal
Correct Answer: B
Solution :
[b] \[(i)\text{ }M{{g}_{(g)}}\to M{{g}^{\oplus }}_{(g)}+{{e}^{-}},\text{ }I{{E}_{1}}=178kcalmo{{l}^{-1}}\] \[(ii)\text{ }M{{g}^{\oplus }}_{(g)}\to M{{g}_{(g)}}^{2+}+{{e}^{-}},\,\,\,I{{E}_{2}}=348kcalmo{{l}^{-1}}\] Adding (i) and (ii), we have \[M{{g}_{(g)}}\to M{{g}^{2+}}_{(g)}+2{{e}^{-}}\] \[\therefore E=I{{E}_{2}}+I{{E}_{2}}=178+348=526kcal\]You need to login to perform this action.
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