A) positive
B) negative
C) zero
D) dependent on the sign of b
Correct Answer: A
Solution :
[a] \[D={{b}^{2}}-4a<0\Rightarrow a>0\] Therefore the graph is concave upwards. \[f(x)>0,\forall x\in R\] \[\Rightarrow f(-1)>0\] \[\Rightarrow a+b+1>0\]You need to login to perform this action.
You will be redirected in
3 sec