A) \[\bar{\omega }\]
B) -\[\bar{\omega }\]
C) \[\omega \]
D) -\[\omega \]
Correct Answer: B
Solution :
[b] Let\[\left| z \right|=\left| \omega \right|=r\] |
\[\therefore z=r{{e}^{i\theta }},\omega =r{{e}^{i\theta }}\] |
Where \[\theta +\phi =\pi \] |
\[\therefore \overline{\omega }=r{{e}^{-i\phi }}\] |
\[\therefore z=r{{e}^{i(\pi -\phi )}}=r{{e}^{i\pi }}{{e}^{-i\phi }}=r{{-e}^{-i\phi }}=-\overline{\omega }\] |
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