A) \[5/\sqrt{6}\]
B) \[10/\sqrt{6}\]
C) \[8/\sqrt{6}\]
D) None of these
Correct Answer: B
Solution :
[b] Here, \[{{a}^{2}}+2>{{a}^{2}}+1\] Or \[{{a}^{2}}+1=({{a}^{2}}+2)(1-{{e}^{2}})\] Or \[{{a}^{2}}+1=({{a}^{2}}+2)\frac{5}{6}\] Or \[6{{a}^{2}}+6=5{{a}^{2}}+10\] Or \[{{a}^{2}}=10-6=4\] Or \[a=\pm 2\] Latus rectum \[\frac{2({{a}^{2}}+1)}{\sqrt{{{a}^{2}}+2}}=\frac{2\times 5}{\sqrt{6}}=\frac{10}{\sqrt{6}}\]
You need to login to perform this action.
You will be redirected in
3 sec
