A) (-6, -9), (-6, 5), (8, -9), (8, 5)
B) (-6, 9), (-6, -5), (8, -9), (8, 5)
C) (-6, -9), (-6, 5), (8, 9), (8, 5)
D) (-6, -9), (-6, 5), (8, -9), (8, -5)
Correct Answer: A
Solution :
[a] Let \[x=\alpha ,x=b,y=c\] and \[y=d\]be the sides of the square. The length of each diagonal of the square is equal to the diameter of the circle, i.e., \[2\sqrt{98.}\] Let \[l\]be the length of each side of the square. Then, \[2{{l}^{2}}={{(Diagonal)}^{2}}\]or \[l=14\] Therefore, each side of the square is at a distance 7 form the center (1,-2) of the given circle. This implies that \[a =-6,b=8,\]\[c=-9\], and d=5. Hence, the vertices of the square are (-6,-9)(-6,5),(8,-9) and (8,5).
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