A) 0
B) 1
C) 3
D) none of these
Correct Answer: C
Solution :
[c] \[\left| x-\frac{1}{2} \right|\] is continuous everywhere but not differentiable at \[x=\frac{1}{2}\], \[\left| x-1 \right|\]is continuous everywhere but not differentiable at x=1, and tan x is continuous in [0, 2] except at \[x=\frac{\pi }{2}\]. Hence, \[f(x)\] is not differentiable at \[x=\frac{1}{2},1,\frac{\pi }{2}.\]You need to login to perform this action.
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