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JEE Main & Advanced Chemistry Coordination Chemistry Question Bank Mock Test - Coordination Compounds

  • question_answer
    Match List I (complex ions) with List II (CFSE) and select the correct answer using the codes given below the list;
    List I                     List II
    (P) \[{{[Mn({{H}_{2}}{{O}_{6}})]}^{2+}}\] 1. \[-\]0.6 \[{{\Delta }_{0}}\]
    (Q) \[{{[Cr({{H}_{2}}{{O}_{6}})]}^{2+}}\] 2. \[-\]0.4 \[{{\Delta }_{0}}\]
    (R) \[{{[Fe({{H}_{2}}{{O}_{6}})]}^{2+}}\] 3. 0
    (S) \[{{[Cr({{H}_{2}}{{O}_{6}})]}^{3+}}\] 4. \[-\]1.2 \[{{\Delta }_{0}}\]
    Code:

    A) P\[\to \]3,           Q\[\to \]1,          R\[\to \]2,           S\[\to \]4

    B) P\[\to \]1,           Q\[\to \]2,          R\[\to \]3,           S\[\to \]4

    C) P\[\to \]4,           Q\[\to \]3,          R\[\to \]2,           S\[\to \]1                       

    D) None of these

    Correct Answer: A

    Solution :

    [a]
    \[CFSE=(-0.4x+0.6y)\]\[{{\Delta }_{0}}+2P\]
    \[P\,\,M{{n}^{2+}}\] \[{{d}^{5}}\] \[t_{2g}^{3}e_{g}^{2}\] 0
    \[Q\,\,C{{r}^{2+}}\] \[{{d}^{4}}\] \[t_{2g}^{3}e_{g}^{1}\] \[-0.6{{\Delta }_{0}}\]
    \[R\,\,F{{e}^{2+}}\] \[{{d}^{6}}\] \[t_{2g}^{4}e_{g}^{2}\] \[-0.4{{\Delta }_{0}}\]
    \[S\,\,C{{r}^{3+}}\] \[{{d}^{3}}\] \[t_{2g}^{3}e_{g}^{0}\] \[-0.2{{\Delta }_{0}}\]


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