question_answer

The correct order of magnetic moments (spin values in B.M.) among is:

A) \[{{[Fe{{(CN)}_{6}}]}^{4-}}>{{[CoC{{l}_{4}}]}^{2-}}>{{[MnC{{l}_{4}}]}^{2-}}\]

B) \[{{[MnC{{l}_{4}}]}^{2-}}>{{[Fe{{(CN)}_{6}}]}^{4-}}>{{[CoC{{l}_{4}}]}^{2-}}\]

C) \[{{[Fe{{(CN)}_{6}}]}^{4-}}>{{[MnC{{l}_{4}}]}^{2-}}>{{[CoC{{l}_{4}}]}^{2-}}\]

D) \[{{[MnC{{l}_{4}}]}^{2-}}>{{[CoC{{l}_{4}}]}^{2-}}>{{[Fe{{(CN)}_{6}}]}^{4-}}\] (Atomic no. of Mn = 25, Fe = 26, Co = 27)

Correct Answer: D

Solution :

[d] \[\therefore \]Number of unpaired electrons=5 \[\therefore \]Number of unpaired electrons=3 \[\therefore \]Number of unpaired electrons=0 As we know that the greater the number of unpaired electrons, greater the magnitude of magnetic moment, Hence the correct order will be. \[{{[Mnc{{l}_{4}}]}^{2-}}>{{[CoC{{l}_{4}}]}^{2-}}>{{[Fe{{(CN)}_{6}}]}^{4-}}\]