A) \[\frac{1}{6}m\]
B) \[\frac{1}{3}m\]
C) \[25m\]
D) \[50m\]
Correct Answer: C
Solution :
[c] Potential gradient \[x=\left( \frac{12}{8+16} \right)\times 4=2V{{m}^{-1}}\] Effective emf of \[{{E}_{1}}\]and \[{{E}_{2}}\] \[E=\frac{\frac{{{E}_{2}}}{{{r}_{2}}}-\frac{{{E}_{2}}}{{{r}_{1}}}}{1/{{r}_{1}}+1/{{r}_{2}}}=\frac{1}{2}volt\] Balancing length\[=\left( \frac{1}{2} \right)\left( \frac{1}{2} \right)=\frac{1}{4}m=25cm\]You need to login to perform this action.
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