A) \[E=2V,\,r=0.5\,\Omega \]
B) \[E=2V,\,r=0.4\,\Omega \]
C) \[E>2V,\,r=0.5\,\Omega \]
D) \[E>2V,\,r=0.4\,\Omega \]
Correct Answer: B
Solution :
[b] V=E-ir. When i=0, the potential reading is 2 V. hence emf is 2V. When V=0, i=5A. This gives \[r=0.4\Omega \]You need to login to perform this action.
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