A) fused with KOH/air, electrolytic oxidation
B) fuse with cone. HN03/air, electrolytic oxidation
C) fused with KOH/air, electrolytic reduction
D) All are correct
Correct Answer: A
Solution :
[a] \[2Mn{{O}_{2}}\xrightarrow[Oxidation\,with\,air]{Fused\,with\,KOH}MnO_{4}^{2-}\] and \[MnO_{4}^{2-}\xrightarrow[in\,alkaline\,solution]{Electrolytic\,oxidation}MnO_{4}^{-}\]You need to login to perform this action.
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