question_answer

\[FeC{{r}_{2}}{{O}_{4}}\] (chromite) is converted to Cr by following steps: Chromite \[\xrightarrow{I}N{{a}_{2}}Cr{{O}_{4}}\]\[\xrightarrow{II}C{{r}_{2}}{{O}_{3}}\xrightarrow{III}Cr,\,\] I, II and III are

A)

I	II	III
\[N{{a}_{2}}C{{o}_{3}}/air,\Delta \]	C	C

B)

I	II	III
\[NaOH/air,\Delta \]	C,\[\Delta \]	Al,\[\Delta \]

C)

I	II	III
\[NaOH/air,\Delta \]	C,\[\Delta \]	Mg,\[\Delta \]

D)

I	II	III
cone. \[{{H}_{2}}S{{O}_{4}},\Delta \]	\[N{{H}_{4}}Cl\]	C,\[\Delta \]