A) abc
B) \[{{a}^{2}}{{b}^{2}}{{c}^{2}}\]
C) bc+ca+ab
D) none of these
Correct Answer: D
Solution :
[d] Applying \[{{R}_{1}}\to a{{R}_{1}},\,\,{{R}_{2}}\to b{{R}_{2}}\] and \[{{R}_{3}}\to c{{R}_{3}}\], we get = Applying \[{{C}_{3}}\to {{C}_{3}}+{{C}_{1}}\]and taking \[(bc+ca+ab)\]common, we get [\[\therefore \]\[{{C}_{2}}\]and \[{{C}_{3}}\]are identical]You need to login to perform this action.
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