question_answer

 A cube of side \[a\] is placed on an inclined plane of inclination \[\theta \]. What is the maximum value of 9 for which the cube will not topple?

A) \[15{}^\circ \]             

B) \[30{}^\circ \]     

C) \[45{}^\circ \] 

D) \[69{}^\circ \]

Correct Answer: C

Solution :

[c] The cube will not topple until the line of action of CM passes through the cube. That is, \[\tan \theta =\frac{AX}{OX}=\frac{a/2}{a/2}\]or \[\theta =45{}^\circ \]