A) \[2K\]
B) \[\frac{K}{2}\]
C) \[\frac{K}{4}\]
D) \[4K\]
Correct Answer: B
Solution :
[b] \[KE=,\frac{{{L}^{2}}}{2I}\,\,\,\,\,L\] remains constant. \[I\] Doubles so KE becomes half.You need to login to perform this action.
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