JEE Main & Advanced Chemistry Electrochemistry / विद्युत् रसायन Question Bank Mock Test - Electrochemistry

  • question_answer
    Electrode potential data are given below. \[F{{e}^{3+}}~\left( aq \right)\text{+}{{\text{e}}^{-}}\to F{{e}^{2+}}\left( aq \right);\]    \[E{}^\circ =+\,0.77\] \[A{{l}^{3+}}\left( aq \right)\text{+3}{{\text{e}}^{-}}\to \text{Al(s);}\]         \[E{}^\circ \text{ }=-\,1.66\text{ }V\] \[B{{r}_{2}}(aq)+2{{e}^{-}}\to 2B{{r}^{-}}(aq);\]    \[E{}^\circ =+\,1.08V\] Based on the data given above, reducing power of \[F{{e}^{2+}}\], Al and \[B{{r}^{-}}\] will increase in the order

    A) \[B{{r}^{-}}<F{{e}^{2+}}<Al\]

    B) \[F{{e}^{2+}}<Al<B{{r}^{-}}\]

    C) \[Al<B{{r}^{-}}<F{{e}^{2+}}\]

    D) \[Al<F{{e}^{2+}}<B{{r}^{-}}\]

    Correct Answer: A

    Solution :

    [a] The lowest the standard reduction potential, the highest is the reducing power.


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