A) increase the E and shift equilibrium to the left
B) lower the E and shift equilibrium to the right
C) increase the E and shift equilibrium to the right
D) lower the E and shift equilibrium to the left
Correct Answer: C
Solution :
[c] \[Zn(s)+2{{H}^{+}}(aq)\rightleftharpoons Z{{n}^{2+}}(aq)+{{H}_{2}}(g)\] \[{{E}_{cell}}=E_{cell}^{o}-\frac{0.059}{2}\log \frac{[Z{{n}^{2+}}][{{H}_{2}}]}{{{[{{H}^{2}}]}^{2}}}\] Addition of \[{{H}_{2}}S{{O}_{4}}\]will increase \[[{{H}^{+}}]\]and \[{{E}_{cell}}\]will also increase and the equilibrium will shift towards right.You need to login to perform this action.
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