A) 111.0 S
B) 1.11 S
C) 222.05 S
D) 1111 S
Correct Answer: C
Solution :
[c] Radius \[=\frac{4.0}{2}=2.0mm=2\times {{10}^{-3}}m;l=2m\] Area of cross section and resistance (R) is related to the resistivity as, (Specific resistance), the length and area by \[R=\text{Resistivity}\times \frac{\text{Length}}{\text{Area}}\] \[=\frac{2.834\times {{10}^{-8}}\Omega m\times 2.00m}{\pi {{(2.0\times {{10}^{-3}}m)}^{2}}}\] \[=4.5\times {{10}^{-3}}\Omega \] Conductance\[=\frac{1}{R}=\frac{1}{1.5\times {{10}^{-3}}}=222{{\Omega }^{-1}}(S)\]
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